ANALISIS DE CIRCUITOS EN INGENIERIA HAYT 7 EDICION PDF

Embed Size px x x x x Circuit diagram not shown. If the DMM appears as a short, then all 5 A flows through the DMM, and none through the resistors, resulting in a false reading of 0 V for the circuit undergoing testing. None of the conditions specified in a to d can be met by this circuit.

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Embed Size px x x x x Circuit diagram not shown. If the DMM appears as a short, then all 5 A flows through the DMM, and none through the resistors, resulting in a false reading of 0 V for the circuit undergoing testing. None of the conditions specified in a to d can be met by this circuit. All Rights Reserved. Proof One possible solution: 11 mA, 1 k, 1 k One possible solution: 9 V in series with 5 1- resistors R1 and 5 1- resistors R2 R5. Impossible; 76 mW Current source is 7.

The final circuit is an 8. This means the Thvenin equivalent must apply to the specific current of a particular circuit one model is not suitable for all operating conditions. There is no conflict with our derivation concerning maximum power.

This is the minimum, not the maximum, power that the battery can deliver to a load. Although the network may be simplified, it is not possible to replace it with a three-resistor equivalent. One possible solution of many: I Is Post on May Category: Technology 31 download. Now invoke Ohms law. Many possible solutions. Hint: Start with finding resistivity, then choose geometry.

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Many possible solutions. Hint: Start with finding resistivity, then choose geometry. All Rights Reserved. If the DMM appears as a short, then all 5 A flows through the DMM, and none through the resistors, resulting in a false reading of 0 V for the circuit undergoing testing.

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